Question

a^2 (a^2-1)(b^2-1)(c^2-1)÷a (a-1)(b-1)(c-1)​

Answer 1

Question -

$\frac{ {a}^{2}( {a}^{2} - 1)( {b}^{2} - 1)( {c}^{2} - 1)}{a(a - 1)(b - 1)(c - 1)}$

Solution -

=$\frac{ {a}^{2}( {a}^{2} - 1)( {b}^{2} - 1)( {c}^{2} - 1)}{a(a - 1)(b - 1)(c - 1)}$

=$\frac{ {a}^{2} ( {a}^{2} - {1}^{2} )( {b}^{2} - {1}^{2} )( {c}^{2} - {1)}^{2} }{a(a - 1)(b - 1)(c - 1)}$

=$\frac{ {a}^{2} (a + 1)(a - 1)(b + 1)(b - 1)(c + 1)(c - 1)}{a(a - 1)(b - 1)(c - 1)}$

=$a(a + 1)(b + 1)(c + 1)$