Math, asked by fatimakhan9386, 10 months ago

தர‌ப்ப‌ட்டு‌ள்ள பு‌ள்‌ளிக‌ள் ஒரு கோடமையு‌ம் பு‌ள்‌‌ளிகளா என ஆரா‌ய்க

(a,-2)(a,3)(a,0)

Answers

Answered by prateek1902
0

Answer:

please write it in English then I will solve the problem

Answered by steffiaspinno
0

விளக்கம்:

\begin{aligned}&x_{1} y_{1} x_{2} y_{2}\\&A(a,-2), \quad B(a, 3), \quad C(a, 0)\end{aligned}

AB ன் தொலைவு

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

\begin{aligned}&=\sqrt{(a-a)^{2}+(3+2)^{2}}\\&=\sqrt{0^{2}+5^{2}}\end{aligned}

\begin{aligned}&=\sqrt{5^{2}}\\&=5\end{aligned}

BC  ன் தொலைவு

d =\begin{array}{l}\sqrt{\left(x_{2}+x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} \\=\sqrt{(a-a)^{2}+(0-3)^{2}}\end{array}

\begin{aligned}&=\sqrt{0^{2}+(-3)^{2}}\\&=\sqrt{+9}\end{aligned}

\begin{aligned}&=\sqrt{9}\\&=3\end{aligned}

CA ன் தொலைவு

\begin{array}{l}=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} \\=\sqrt{(a-a)^{2}+(0+2)^{2}}\end{array}

\begin{aligned}&=\sqrt{o^{2}+2^{2}}\\&=\sqrt{2^{2}}\end{aligned}

=2\\B C+C A=3+2 \\  \end{aligned}

=5\\

=AB

கொடுக்கப்பட்டுள்ள பு‌ள்‌ளிக‌ள் ஒரு கோடமையு‌ம் பு‌ள்‌‌ளிகளாகும்.    

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