Question

(a^2-a)(4a^2-4a-6)
someone one please help I need the answer ASAP

Answer 1

Answer:

$({a}^2- a)({4a}^2-4a- 6 )$

by multiplying .

$({a}^2({4a}^2-4a- 6 )- (a)({4a}^2 - 4a - 6 )$

$({4a}^4 - {4a}^3 - {6a}^2 )- ({4a}^3 + {4a}^2 + 6a )$

$({4a}^4 - {8a}^3 - {2a}^2 + 6a )$