If the areas of three adjacent faces of a cuboidal box be 40cm square, 30cm square, 12cm square respectively, then find the volume of the box
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Answered by
53
Solutions :-
Given :
The areas of three adjacent faces of a cuboidal box be 40 cm², 30 cm², 12 cm² respectively.
Find the volume of the box :-
We know that,
Volume of cuboid = lbh cu. unit
So, √(l × b × l × h × b × h) cu. unit
= √(40 × 30 × 12) cm³
= √ 14400 cm³
= 120 cm³
Hence,
Volume of the box = 120 cm³
Given :
The areas of three adjacent faces of a cuboidal box be 40 cm², 30 cm², 12 cm² respectively.
Find the volume of the box :-
We know that,
Volume of cuboid = lbh cu. unit
So, √(l × b × l × h × b × h) cu. unit
= √(40 × 30 × 12) cm³
= √ 14400 cm³
= 120 cm³
Hence,
Volume of the box = 120 cm³
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Answered by
98
Solutions :-
We have
Area of three adjacent faces of a cuboidal box be 40cm square, 30cm square, 12cm square respectively.
We know,
Volume of Cuboidal box = lbh cubic units
![\sqrt{area \: \: of \: \: three \: \: adjacent \: \: faces} \\ \\ \sqrt{40 \times 30 \times 12} \\ \\ = \sqrt{14400} = 120 \sqrt{area \: \: of \: \: three \: \: adjacent \: \: faces} \\ \\ \sqrt{40 \times 30 \times 12} \\ \\ = \sqrt{14400} = 120](https://tex.z-dn.net/?f=+++%5Csqrt%7Barea+%5C%3A++%5C%3A+of+%5C%3A++%5C%3A+three+%5C%3A++%5C%3A+adjacent+%5C%3A++%5C%3A+faces%7D+%5C%5C++%5C%5C+%5Csqrt%7B40+%5Ctimes+30+%5Ctimes+12%7D++%5C%5C++%5C%5C++%3D++%5Csqrt%7B14400%7D++%3D+120)
Hence,
Volume of cuboidal box = 120 cm
We have
Area of three adjacent faces of a cuboidal box be 40cm square, 30cm square, 12cm square respectively.
We know,
Volume of Cuboidal box = lbh cubic units
Hence,
Volume of cuboidal box = 120 cm
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