Question

a^2+b^2=160 ab=60 then a^2- b^2=? ​

Answer 1

Answer:

105.83

Step-by-step explanation:

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ = > {(a + b)}^{2} = 160 + 2 \times 60 \\ = > {(a + b)}^{2} = 160 + 120 \\ = > {(a + b)}^{2} = 280 \\ = > a + b = \sqrt{280}$

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ = > {(a - b)}^{2} = 160 - 2 \times 60 \\ = > {(a - b)}^{2} = 160 - 120 \\ = > {(a - b)}^{2} = 40 \\ = > a - b = \sqrt{40}$

$(a + b)(a - b) = {a}^{2} - {b}^{2} \\ = > \sqrt{280} \times \sqrt{40} = {a}^{2} - {b}^{2} \\ = > {a}^{2} - {b}^{2} = \sqrt{11200} = 105.83$

Answer 2

Answer:

105.83 is your answer mate......

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