Math, asked by nimay63, 1 year ago

(a^2- b^2)^2 expand it​

Answers

Answered by crazyengineer
0

 {a}^{2}  -  {b }^{2}  ={ a - b}{a + b} \\ therefore \: this \: can \: be \: expended \: a \: follows \\ {a + b}{a - b}{a + b}{a - b}

Answered by Darsh05
2

Answer:

(a^{2} -b^{2} )^{2}\\=[(a+b)(a-b)]^{2}\\=(a+b)^{2}* (a-b)^{2} \\=(a^{2} +b^{2} +2ab)*(a^{2}+ b^{2} -2ab)\\=a^{2}*(a^{2}+ b^{2} -2ab)+b^{2}*(a^{2}+ b^{2} -2ab)+2ab(a^{2}+ b^{2} -2ab)\\=a^{4} +a^{2} b^{2} -2a^{3} b+a^{2} b^{2}+b^{4} -2ab^{3} +2a^{3} b+2ab^{3}-4a^{2} b^{2}\\=a^{4}-2a^{2} b^{2}+b^{4}

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