Math, asked by RohitSP8622, 11 months ago

A^2-b^2=369 and a+b=41 then find a

Answers

Answered by sandy1816
10

Step-by-step explanation:

a²-b²=369

(a-b)(a+b)=369

(a-b)41=369

a-b=9

a=b+9........(1)

a+b=41

b+9+b=41

2b=32

b=16

(1) a=16+9=25

Answered by koushikj401
6

a^2-b^2=369

a+b=41

b=41-a

a^2-(41-a)^2=369

a^2-(1681+a^2-82a)=369

a^2-1681-a^2+82a=369

82a-1681=369

82a=369+1681

82a=2050

a=2050/82

a=25

mark me as brainliest please

Similar questions