Question

a = 2 , b= 2
(a^a+b^b)^-1​

Answer 1

Step-by-step explanation:

If a^2 + b^2 - ab - a - b +1 leq 0, a, b in R and f(x) = (1+ secx) (1 + sec2x) (1 +sec2^2 x)....(1+sec2^n x), then f(pi/2^n) is

Answer 2

Answer:

1/8

Step-by-step explanation:

a=2,b=2

So, (a²+b²)^-1=(2²+2²)^-1

=(4+4)^-1=8^-1

When any digit is multiplied with a power in negative, the dogit reciprocals.

So 8^-1=1/8