(a^2+b^2)/(a-b)^2
and a=4 then
What is b?
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Answer:
Step-by-step explanation:
First of all let understand this:
“(a+b)^2=(a-b) ^2+4ab”
Therefore, (a^2+b^2)^2=(a^2-b^2)^2+4a^2b^2
Now, according to the question
a^2-b^2=4. And. ab=2
Putting the value in the derived equation,
(a^2+b^2)^2=(4)^2+4(2)^2
=16+16=32
a^2+b^2= 4√2. :-)
Hope it help you !
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