Math, asked by dineshyepuri05, 2 months ago

(a^2+b^2)/(a-b)^2
and a=4 then
What is b?​

Answers

Answered by shubhamkh9560
0

Answer:

Step-by-step explanation:

First of all let understand this:

“(a+b)^2=(a-b) ^2+4ab”

Therefore, (a^2+b^2)^2=(a^2-b^2)^2+4a^2b^2

Now, according to the question

a^2-b^2=4. And. ab=2

Putting the value in the derived equation,

(a^2+b^2)^2=(4)^2+4(2)^2

=16+16=32

a^2+b^2= 4√2. :-)

Hope it help you !

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