Question

A ^2 + b ^2 + c ^2- 2 b + 6c =-10 then the value of a + b + C =

Answer 1

We have : 2a = 3b = 6c ,

Let , 2a = 3b = 6c = k , So

2a = k ⇒2a1a = k 1a ⇒2 = k 1a --- ( 1 )And 3b = k ⇒3b1b = k 1b ⇒3 = k 1b --- ( 2 )And 6c = k ⇒6c1c = k 1c ⇒6 = k 1c ⇒2 × 3 = k 1c , Substitute values from equation 1 and 2 and get ⇒ k 1a× k 1b = k 1c ⇒ k 1a+ 1b = k 1c , So ⇒ 1c = 1a+ 1b ⇒ 1c = a + ba b ⇒ c= aba + b