(a^2-b^2)c + (b^2-c^2)a
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Factorisation,
We have,
(a²-b²)c + (b²-c²)a
= a²c - b²c + ab²-ac²
= a²c - ac²+ ab² - b²c
= ac(a - c) + b²(a - c)
= (a - c)(ac + b²)
That's it
Hope it helped (≧▽≦)
We have,
(a²-b²)c + (b²-c²)a
= a²c - b²c + ab²-ac²
= a²c - ac²+ ab² - b²c
= ac(a - c) + b²(a - c)
= (a - c)(ac + b²)
That's it
Hope it helped (≧▽≦)
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= (a ^2- b ^2)c + ( b ^2- c ^2)a
=a ^2c- b ^2 c + b ^2a - c ^2a
=a ^2 c - c ^2a + b ^2 a - b ^2c
=ac (a-c) + b ^2 (a-c)
= (a-c) (ac + b ^2).
=a ^2c- b ^2 c + b ^2a - c ^2a
=a ^2 c - c ^2a + b ^2 a - b ^2c
=ac (a-c) + b ^2 (a-c)
= (a-c) (ac + b ^2).
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