Question

A=2 b=3 then find (a^b+b^a)^-1

Answer 1

(a^b + b^a)¯¹ = (2³+3²)¯¹ = (8+9)¯¹ = (17)¯¹ = 1/17

Answer 2

Answer:

1/17

Step-by-step explanation:

Given -

($a^{b}$ + $b^{a}$)^-1

=  (2³ + 3²)-1

= (8 + 9)-1

= 17-1

= 1/17