Math, asked by senparnika2007, 9 months ago

a^2(b+c)-b^2(c+a)+c^2(a+b)+3abc​

Answers

Answered by Anonymous
1

Answer:

what do you want of this ?

Answered by Dhanvanth05
5

Answer

(a+b+c)(ab+bc+ac)−3abc(a+b+c)(ab+bc+ac)−3abc

=a2b+abc+ac2+ab2+b2c+abc+abc+bc2+ac2−3abc=a2b+abc+ac2+ab2+b2c+abc+abc+bc2+ac2−3abc

=ab2+a2b+bc2+b2c+ac2+a2c+3abc−3abc=ab2+a2b+bc2+b2c+ac2+a2c+3abc−3abc

=a(b2)+b(a2)+b(c2)+(b2)c+a(c2)+(

Step-by-step explanation:

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