Question

A^2 +c^2 +17=2(a-2b^2-8b), then the value of (a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2] is

Answer 1

Answer:

(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

⇒(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

Given,

ab+bc+ca=10,a

2

+b

2

+c

2

=16

⇒(a+b+c)

2

=16+2(10)

a+b+c=

16+20

=6

Step-by-step explanation:

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