Question

a long straight wire carrying current produces of magnetic induction of 4×10-6​at a point 15cm from the wire.Calculate the current through the wire?​

Answer 1

Answer

Answer

Correct option is

B

3.2×10

−16

N

Given magnetic field

B

^

=2×10

−4

Wbm

−2

velocity of electronv=10

7

m/s

charge of electron q=1.6×10

−19

C

We know magnetic forceF=qvBsinθ

F=1.6×10

−19

×10

7

×2×10

−4

=3.2×10

−16

Here θ=90 as mentioned electrons moving in a perpendicular direction to the wire viz. sin90=1

Hope it helps...

Answer 2

Explanation:

5×10−4

Magnetic field induction at point P due to current carrying wire is 

B2=2πrμ0i.2π×0.024π×10−7×30

B2=3×10−4T

The direction of B2 will be perpendicular to B1 then, the magnitude of the resultant magnetic induction 

B=B12+B22

=(4)2+(3)2×10−4

=5×10−⁴T

hope it helps uh!

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