a 2. cm high object is placed at a distance of 32cm from a concave mirror . the image is real inverted and 3cm in size .find the focal length of the mirror and the position of the image
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Answered by
7
Given :
object distance=-20cm [ sign conventions]
Image distance=v=?
focal length=f=-15cm
Formula to be used:
1/f=1/u+1/v
1/v=1/f-1/u
=-1/15+1/20
= -4+3/60
=-1/60
v=-60 cm
hence object is placed between F and c and image formed is beyond C .
Nature of image:
-->Real AND INVERTED
--->MAGNIFIED
--->AT A DISTANCE OF 60CM FROM THE MIRROR.
Object height=ho=3cm
Image height=?
magnification=m=-v/u
=60/-20
=-3
m=hi/ho
hi=mxho
object distance=-20cm [ sign conventions]
Image distance=v=?
focal length=f=-15cm
Formula to be used:
1/f=1/u+1/v
1/v=1/f-1/u
=-1/15+1/20
= -4+3/60
=-1/60
v=-60 cm
hence object is placed between F and c and image formed is beyond C .
Nature of image:
-->Real AND INVERTED
--->MAGNIFIED
--->AT A DISTANCE OF 60CM FROM THE MIRROR.
Object height=ho=3cm
Image height=?
magnification=m=-v/u
=60/-20
=-3
m=hi/ho
hi=mxho
Answered by
2
v=-48cm and f=-19.2 cm
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