Math, asked by shubhamksinghdps658, 9 months ago

a=2 d=8. Sn=90. an=? ​

Answers

Answered by yashpaingankar
1

Answer:

Sn=n/2[2a+(n-1)d]

90=n/2[2×2+(n-1)×8]

180=n[4+8n-8]

180=8n^2-4n

8n^2-4n-180=0

2n^2-n-45=0

2n^2-10n+9n-45=0

2n(n-5)+9(n-5)=0

(2n+9)(n-5)=0

n=-4.5 or 5

n=5 (accept only natural numbers)

an=2×5

an=10

Answered by daksh2965
1

Step-by-step explanation:

sn=n/2(2a+(n-1)D)

90 =  \frac{n}{2} (2(2) +( n - 1)8)

90 =  \frac{n}{2}  \times 2(2 + (n - 1)4)

90 = n(2 + 4n - 4)

90 = 4 {n}^{2}  - 2n

2 {n}^{2}  - n - 45 = 0

2 {n}^{2}  - 10n + 9n - 45 = 0

2n(n - 5) + 9(n - 5) = 0

n = 5

an=a+(n-1)D

an=2+4(8)

an=34

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