a 2 digit no. is 4 times the sum of its digits.. if 36 is aded to the no. .. its digits are reversed.. find the no.
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let the tens digit of the number be x and the unit digit be y,
then the number will be = 10x+y
10x+y = 4(x+y)
10x+y = 4x+4y
6x-3y = 0 ----------------(1)
10x+y +32 = 10y+x
9x-9y = -36 -------------(2)
By solving equation (1)&(2) we get ;
18x-9y= 0
9x - 9y = -36
9x = 36
x = 4
6x-3y =0
6×4 =3y
y = 8
therefore the number is
10x +y = 48
hope this helped you ............ !
then the number will be = 10x+y
10x+y = 4(x+y)
10x+y = 4x+4y
6x-3y = 0 ----------------(1)
10x+y +32 = 10y+x
9x-9y = -36 -------------(2)
By solving equation (1)&(2) we get ;
18x-9y= 0
9x - 9y = -36
9x = 36
x = 4
6x-3y =0
6×4 =3y
y = 8
therefore the number is
10x +y = 48
hope this helped you ............ !
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