A 2-digit number has tens digit greater than the unit's digit. if the sum of its digits is equal to twice and difference, how many such numbers are possible?
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there are only 3 no.s = 31,62,93
solution : let's assume that no be 10x + y
A/Q : x>y and x + y = 2(x - y) ⇒ x=3y
so from hit and trial method ans would be 31,62,93
hope so right
solution : let's assume that no be 10x + y
A/Q : x>y and x + y = 2(x - y) ⇒ x=3y
so from hit and trial method ans would be 31,62,93
hope so right
MohdIrfan:
Are u sure that it is right ans.
well I guess so .........what's the actual answer in ur assignment ?
it's number can be possible 1,2,3 and 4.
And in my book anssheet it's ans will be 1
and what's that no. ?
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