A 2-digit number is 3 times the sum of its digits. If 45 is added to the number, its digits are interchanged. The sum of digits of the number is
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Let ones digit be x
tens digit be y
ATQ
Number=10x+y
After interchanging=10y+x
So
10x+y+45=10y+x
10x-x+y-10y= -45
9x-9y= -45
9(x-y)= -45
(x-y)= -45÷9
x-y=-5
x=-5+y
x+y=3{10x+y}
-5+y+y=30x+3y
-5+2y-3y=30x
-5-y=30x
-y-30x=5
sorry I can't solve after this
-(y+30x)=5
tens digit be y
ATQ
Number=10x+y
After interchanging=10y+x
So
10x+y+45=10y+x
10x-x+y-10y= -45
9x-9y= -45
9(x-y)= -45
(x-y)= -45÷9
x-y=-5
x=-5+y
x+y=3{10x+y}
-5+y+y=30x+3y
-5+2y-3y=30x
-5-y=30x
-y-30x=5
sorry I can't solve after this
-(y+30x)=5
Answered by
0
Answer:
Step-by-step explanation:
(x,y)=3(x+y)------------(1)
(x,y)+45=54
i.e, (x,y)=54-45=9
therefore,probable digits r (1,8),(2,7),(3,6),(4,5)..etc
among these,(2,7) is suitable.
so,9 is the answer.
verify:
27+45=72.
or, from(1), 27=3*(2+7)
=3*9
=27
hence verified.
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