a 2 digit number is 4 times the sum of its digits and twice of product of digits find the number
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Given that the two digit number = 4 times sum of its digits.
⇒ 10y + x = 4(x + y)
⇒ 10y + x = 4x + 4y.
⇒ 3x – 6y = 0.
Given that the two digit number = 4 times sum of its digits.
⇒ 10y + x = 4(x + y)
⇒ 10y + x = 4x + 4y.
⇒ 3x – 6y = 0.
tanmayanilmahalley:
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let the two digit number is XY
XY can be written as 10X+Y
Given that
1.)10x+y= 4(x+y)
2.)10x+y= 2xy
solving these
10x+y=4x+4y
6x=3y
y=2x
put this value in equation 2
10x +2x= 2x(2x)
12x= 4x^2
4x^2-12x=0
4x(x-3)=0
x=0,&3
to be 2digit number,,x can't be 0
therefore x= 3 & y=2x= 2x3= 6
2digit number = 36
XY can be written as 10X+Y
Given that
1.)10x+y= 4(x+y)
2.)10x+y= 2xy
solving these
10x+y=4x+4y
6x=3y
y=2x
put this value in equation 2
10x +2x= 2x(2x)
12x= 4x^2
4x^2-12x=0
4x(x-3)=0
x=0,&3
to be 2digit number,,x can't be 0
therefore x= 3 & y=2x= 2x3= 6
2digit number = 36
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