A 2 kg ball is moving at a speed of 4 m/s toward a ball of the same mass at rest. They both stick together after the collision. What is the velocity of the two ball system and what type of collision is it?
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total initial momentum = m1×v1 + m2×v2 = 2×3+3×0 = 6 kgm/s
momentum conserved, hence final momentum 6 = (m1+m2)×v; v = 6/(2+3) = 1.2 m/s
final kinetic energy = (1/2)(m1+m2)v2 =(1/2)×5×1.2×1.2 = 3.6 kgm/s
loss in kinetic energy = 6-3.6 = 2.4 kgm/s
Explanation:
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