a 2 kg body is sliding up an inclined plane of inclination 30° find the work done by the force of the gravity in moving the body through 1m
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Work done = mghsin theta
Work done = 2 kg * sin 30° * g * height cos 180°
= 2kg * 1/2 * -1 * 10
= - 10 Joules.
Work done = 2 kg * sin 30° * g * height cos 180°
= 2kg * 1/2 * -1 * 10
= - 10 Joules.
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