A 2 kg mass is heated for 40 sec by a heater that producen 100J/sec. The specific heat capacaity of copper is 400J What is riše in temperature??
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m= 2kg
t= 40s
P= 100J/s
C= 400J/kg°C
Q= P×t
= 100×40= 4000J
Q= m×C×∆t
4000= 2×400×∆t
∆t= 4000/(2×400)
∆t= 5°C
t= 40s
P= 100J/s
C= 400J/kg°C
Q= P×t
= 100×40= 4000J
Q= m×C×∆t
4000= 2×400×∆t
∆t= 4000/(2×400)
∆t= 5°C
mimo3:
Q=p×t which formula is this and what p štand for?
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