Question

A 2 kg plate is kept suspended in air by allowing 10 marbles hitting per second with a speed v from the downward direction. If the mass of each marble is 20 g then determine v

Answer 1

Answer:

0.98m/s

Explanation:

Given that:

Mass of disc,M=10g=0.010kg

Mass of each marble,m=5g=0.005kg

Suppose the number of marbles striking the disc per second=n and velocity with which marbles strike disc is v.

Then Weight of disc acting downward=Mg

Change in velocity of marbles when they rebound =v−(−v)=2v

Therefore the change in momentum of each marble when it strikes the disc=m∗2v=2mv

and total momentum imparted per second to the disc=2mnv= The force exerted by the marbles in the upward direction

The disc will remain at rest if the net force acting on it is zero provided it is initially at rest.

Therefore for the disc to remain at rest,

Weight of disc=Upward force on it

=Mg=2mnv

v=

2mn

Mg

=

(2∗0.005∗10)

(0.010∗9.8)

=0.98m/s

Answer 2

Answer:

I am not bro........

...... brother