Question

a=2 r=-2/3 find s6 for a geometric progression​

Answer 1

Answer:

Step-by-step explanation:

a=2 , r=2/3

Sn =a(r^n -1)/r-1

S6=2([2/3]^6 - 1)/2/3 -1

   =1330/243

Answer 2

Answer:

1.09

Step-by-step explanation:

Given,

first term of geometric progression, a= 2

and common ratio, r =  -2/3

We have to calculate sum of first 6 terms of given geometric progression, so n = 6

since, the sum of geometric progression upto six terms$=\ \dfrac{a\times(r^{n}-1)}{r-1}\\\\=\ \dfrac{2\times((\dfrac{-2}{3})^{6}-1)}{\dfrac{-2}{3}-1}\\=\ 1.09$

so the sum of first six terms of given G.P is 1.09 (approx)