Question

a=2+under root 3, find the value of a -1/a​

Answer 1

this is the answer to that question

Answer 2

Answer:

$\frac{6 + 4 \sqrt{3} }{2 + \sqrt{3} }$

Step-by-step explanation:

$given \\ \\ a = 2 + \sqrt{3} \\ \\ then \: the \: value \: of \: a - \frac{1}{a} \: is$

$2 + \sqrt{3} - \: \frac{1}{2 + \sqrt{3} } \\ \\ \frac{ {(2 + \sqrt{3)} }^{2} - 1}{2 + \sqrt{3} } \\ \\ \frac{4 + 3 + 4 \sqrt{3} - 1}{2 + \sqrt{3} } \\ \\ \frac{6 + 4 \sqrt{3} }{2 + \sqrt{3} }$