Water in a Canal, 6m wide and 1.5 m deep is flowing with a speed of 10 km/h . How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed ?
Answers
Answered by
8
Answer:
Step-by-step explanation:
Speed of flowing of water from canal is 10km/h , means length of water flows in 1 hour = 5 km , so length of water flows in 30 minutes = 5km
Now, volume of water flowing from canal = length of water flows in 30 minutes × breadth of canal × deep of canal
= 5000m × 6m × 1.5m = 45000 m³
Let area of field = x m²
Then, volume of water irrigates into the field = area of field × height of water during irrigation
= x m² × 8× 10⁻² m = 0.08x m³
Now, volume of water flowing from canal = volume of water in field
45000 m³ = 0.08x m³
x = 562500 m²
We know, 1 hectare = 10000 m²
So, area of field in hectare = 562500/10000 = 56.25 hectares
sajalraj1611:
of linear equation
Similar questions
Math,
7 months ago
Math,
7 months ago
Economy,
1 year ago
Social Sciences,
1 year ago
History,
1 year ago