A 2 v cell is connected to a 1 ohm resistor. how many electrons comes out of the negative terminal of the cell in 2 min
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resistance of the resistor R=1ohm
e.m.f E=2v
let current in the resistor =I
From ohm's law,
E=IR
2=I x 1
I=2 amperes
charge Q =I x t
time t=2 mins=2x60=120sec.
Q =2x120
Q=240C
Also,Q=ne.
where e is the charge of en electron =1.6x10^-19C
240=n x( -1.6x10^-19)
n=240/1.6x10^-19
n=150x10^19
HENCE, 150x10^19 electrons evolved from the -ve terminal in 2mins or 120 seconds.
e.m.f E=2v
let current in the resistor =I
From ohm's law,
E=IR
2=I x 1
I=2 amperes
charge Q =I x t
time t=2 mins=2x60=120sec.
Q =2x120
Q=240C
Also,Q=ne.
where e is the charge of en electron =1.6x10^-19C
240=n x( -1.6x10^-19)
n=240/1.6x10^-19
n=150x10^19
HENCE, 150x10^19 electrons evolved from the -ve terminal in 2mins or 120 seconds.
Answered by
2
Answer:
resistance of the resistor R=1ohm
e.m.f E=2v
let current in the resistor =I
From ohm's law,
E=IR
2=I x 1
I=2 amperes
charge Q =I x t
time t=2 mins=2x60=120sec.
Q =2x120
Q=240C
Also,Q=ne.
where e is the charge of en electron =1.6x10^-19C
240=n x( -1.6x10^-19)
n=240/1.6x10^-19
n=150x10^19
HENCE, 150x10^19 electrons evolved from the -ve terminal in 2mins or 120 seconds.
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