Question

A 2 x 2 - 3abx + 2b 2 = 0 find the roots of the quadratic equation by formula method

Answer 1

Quadritatic Equation,

As we know that the standard form of a quadritatic equation is as follows

ax²+ bx + c, and the zeros are given by
ax²+ bx + c = 0

Sridhar Acharyas formula for finding the zeros of a quadratic equation is,

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

Here given that,

(ax)²-3abx + 2b² = 0

So, x = [-(-3ab)+-√{(-3ab)²- 4(a)².2b²}]/2a²

or, x = [3ab +-√{9(ab)²- 8(ab)²}]/2a²

or, x = {3ab+-√(ab)²}/2a²

or, x = (3ab + ab)/2a² and x = (3ab - ab)2a²

or, x = 4ab/2a² and x = 2ab/2a²

So, x = 2b/a,b/a

That's it
Hope it helped (^_^)/