Question

A 20.5m long ladder leans on a 20m high wall. How far from the wall is the ladder placed

Answer 1

✰Answer✰

♦️GiveN

• Length of ladder = 20.5 m
• Height of wall= 20m

♦️To FinD

• The distance between foot of ladder and foor of wall.

✰Explanation of Q.✰

↪ Refer to the attachment......

The system is in the form of right angled traingle. Why?! It is because we all know , a wall is always made perpendicular to ground and here the ladder is placed in slanting position with wall.

♦️So, We can say this is a right angled triangle, Ladder is the hypotenuse, the distance between ladder foot and wall foot is base and height of wall is perpendicular.

✰We must know✰

↪ The Pythagoras theoram

$\large{ \boxed{ \tt{ {(base)}^{2} + {(perpendicular)}^{2} = {(hypotenuse)}^{2} }}}$

✰Solution✰

☛By using the above formula,

$\large{ \tt{ \rightarrow \: (base) {}^{2} + {20 \: m \: }^{2} = {(20.5 m)}^{2} }} \\ \\ \large{ \tt{ \rightarrow \: (base) {}^{2} + 400 \: {m}^{2} = 420.25 \: {m}^{2} }} \\ \\ \large{ \tt{ \rightarrow \: (base) {}^{2} = 20.25 \: {m}^{2} }} \\ \\ \large{ \tt{ \rightarrow \: base = \sqrt{20.25} \: \: m }} \\ \\ \large{ \rightarrow{ \boxed{ \tt{ \green{base = 4.5 \: m}}}}}$

$\large{ \tt{ \therefore{ \blue{distance \: between \: foot \: of \: ladder \:}}}} \\ \large{ \tt{ \blue{and \: foot \: of \: wall = 4.5m}}}$