Chemistry, asked by sarfrajAhmad4895, 8 months ago

A 20 μF capacitor is joined to a battery of emf 6.0 V through a resistance of 100 Ω. Find the charge on the capacitor 2.0 ms after the connections are made.

Answers

Answered by shilpa85475
0

The charge on the capacitor 2.0 ms after the connections are made is 76 μC.

Explanation:

Across the capacitor, the growth of charge,  

Q = CV = Q0.e - tRCQ0 = 20 \times 6 \times 10-6 C

⇒Q = 120 \times 10-6. e-2 \times 10-3102.20 \times 10-6

⇒Q = 120 \times 10-6. e-1

Charge on the capacitor =76 μC

A capacitor is an instrument that in an electric field supplies electrical energy. It has with two terminals.  

Similar questions