Math, asked by kyurem1945, 1 year ago

A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more.At the end of the two removals and replacement, what is the ratio of milk and water in the resultant mixture? 1 point

Answers

Answered by ska1933
1
sorry but i dont know
Answered by nandhuds106
0

Answer:

9:1

Step-by-step explanation:

Let Wo be the amount of water in the initial mixture.

Let Wr be the amount of water in the mixture after the replacement have taken place.

⇒ Wo= (2*20)/5=8 Lts                     {Given the ratio as 3:2]

 Wr /Wo  = [(M-R)/M ]^n

Where R is the amount of mixture replaced by milk in each of the steps, M is the total volume of the mixture and n is the number of times the cycle is repeated.

Hence,  

Wr/Wo = [(20-10)/20]^2 = 1/4

∴Wr =Wo/4 =8/4 =2 Lts

Hence, the mixture will have 18L of milk and 2L of water.

∴ ratio of milk and water = 18:2=9:1

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