Question

A 20-m chain was found to be 0.05 m too long after chaining 1400 m. It was found to be 0.1 m too long
after chaining 2200 m. If the chain was correct before the commencement of the work find the true distance​

Answer 1

Answer:

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Step-by-step explanation:

L = 20m L=20m

L' = 20+20.10 /2 =20.05m L' = 20.10 +20.18 / 2 =20.14 m

l1' = 2000m l2' = 2000m

l1 = 20.05 / 20 x 2000 = 2005 l2 = 20.14 / 20 x 2000 =2014

l = l1 + l2 = 2005 + 2014 = 4019m

Answer 2

• $\implies$ L = 20m

• $\implies$ $\sf{L' = \frac{20+20.10}{2 =20.05m}}$

• $\implies$ $\sf{ L' = \frac{ 20.10 +20.18 }{ 2 =20.14 m}}$

• $\implies$ $\sf{l1' = 2000m l2' = 2000m}$

• $\implies$ $\sf{l1 = \frac{20.05}{20 x 2000 } = 2005 l2 = \frac{20.14 }{ 20 x 2000 }=2014}$

• $\implies\sf{ l = l1 + l2 = 2005 + 2014 = \underline{4019m}}$

ans is 4019 m