A 20 m deep well of diameter 7 m. is dug and the earth got by digging is evenly spread out to form a rectangular platform of base 22m × 14m. Find the height of the platform.
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Answered by
1
Volume of well=Volume of rectangular platform
For well
r=3.5mtr
h=20mtr
For rectangle
l=22mtr
b=14mtr
→πr²h=lbh
→22/7×3.5²×20=22×14×h
→770m=308m × h
→770/308=h
→2.5mtr=h
For well
r=3.5mtr
h=20mtr
For rectangle
l=22mtr
b=14mtr
→πr²h=lbh
→22/7×3.5²×20=22×14×h
→770m=308m × h
→770/308=h
→2.5mtr=h
Answered by
2
Answer:
2.5 m
Step-by-step explanation:
Given, Depth of well h = 20 m.
Given, Diameter of well = 7 m.
Then, Radius = 3.5 m
Length of platform = 22 m and breadth = 14 m.
∴ Volume of earth dug = Volume of platform
πr²h = lbh
⇒ 22/7 * (3.5)² * 20 = 22 * 14 * h
⇒ 770 = 308 * h
⇒ h = 2.5 m.
Therefore, Height of platform = 2.5 m.
Hope it helps!
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