Question

a 20 m deep well with diameter 14m is dug up and the earth from digging is spread evenly to form platform 22 M and 14m the height of platform is

Answer 1

From the given data, volume of the cylindrical well=volume of the platform
thus, πr²h=lbh
(22/7)x7x7x20 = 22x14x h     (since dia=14m, r=7m)
           22x140 = 22x14x h
therefore, h=10m
Height of the platform=10m

Answer 2

The height of platform is 10m.

Given:

• A 20 m deep well with diameter 14m is dug up and
• Earth from digging is spread evenly to form platform.
• Length of platform is 22 m and breath 14m.

To find:

• Height of platform

Solution:

Concept used:

Volume of earth taken out = Volume of platform

Step 1:

Well is in the form of cylinder.

So,

Height/Deep of well (h) = 20 m

Radius of well (r)= 14/2 = 7 m

Volume of Well/Cylinder$\bf = \pi \: {r}^{2} h \: {unit}^{3}$

Volume of earth taken out $= \frac{22}{7} \times 7 \times 7 \times 20$

Volume of earth taken out$\bf = 3080 \: {m}^{3}$

Step 2:

Volume of platform/cuboid= l×b×h

So,

$= 22 \times 14 \times h$

Step 3:

Equate both volumes

$22 \times 14 \times h = 3080$

or

$h = \frac{3080}{22 \times 14}$

or

$\bf h = 10 \: m$

Thus,

Height of platform is 10 m.

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