Math, asked by YodABrainly, 4 months ago

A 20 m deep well with diameter 7 m is dug and the earth from digging is evenly spread out to form a platform 22 m by 14 m. Find the height of the platform.​

Answers

Answered by kusamlakhera
3

Answer:

2.5m

Step-by-step explanation:

it's a cylinder,

so volume of cylinder=πr^2h

π=22/7

22/7×35×35/100×20

=770m^3

sides of cuboid=22,14m

22×14=308

Height of cuboid=770÷308

=2.5m

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Answered by Anonymous
11

The height of the platform is 2.5 m.

Explanation :-

It is given that the shape of the well is in the shape of a cylinder with a diameter of 7 m.

⇒ radius = 7/2 m

⇒ Depth (h) = 20 m

Volume of the earth dug out will be equal to the volume of the cylinder.

⇒Volume of cylinder = π × r²× h

⇒Volume of cylinder = 22 × 7 × 5 m³

Let the height of the platform = H

Volume of soil from well (cylinder) = Volume of soil used to make such platform.

⇒ π × r² × h = Area of platform × Height of the platform.

We know that the dimension of the platform is = 22 × 14.

So, Area of platform = 22 × 14 m²

\implies π × × h = 22 × 14 × H

\implies 22 × 7 × 5 = 308 × H

\implies 770 = 308 × H

\implies H = 770/308

\implies H = 2.5 m \red\bigstar

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