Question

A 20-metre length of wire is used to fence a rectangular field with dimensions in the ratio 3 : 1.
Calculate the area of the fi eld.

Answer 1

Heya mate, Here is ur answer

Let the common ratio be x.

Then length=3 x

Breadth= x

Given that the wire required = 20 m .

This wire is fenced around the field. So it also gives the perimeter of the field.

So, Perimeter of the field = 20 m

2(l+ b)=20

2(3x+x)=20

2×4x=20

8x=20

x=20/8

x=2.5

So, length=3×2.5

=7.5 m

Breadth=2.5 m

Area of field=l×b

=7.5×2.5

=18.75 m^2

Warm regards

@Laughterqueen


Be Brainly✌✌✌

Answer 2

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ

ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ

ⓐⓝⓢⓦⓔⓡ



==================================


⊙ Perimeter of a rectangle = 2(l+b)

=> so, let their dimension be x


so,
$2(3x + x) = 20metre$


$2 \times 4x = 20metre$



$8x = 20$



$x = \frac{20}{8} = \frac{5}{2} m$


so, the length is 3x



$3 \times \frac{5}{2} = 7.5m$




so, breadth is x


$\frac{5}{2} = 2.5m$



so,the area of a rectangle is
$l \times b \\ \\ 7.5 \times 2.5 = 18.75m {}^{2}$




$hope \: it \: helps \: you$



$<marquee > prabhudutt$