Question

A = 20°, evaluate
3 sin3A +2cos (2A +5°)/2cos3A-sin(2A-10°)​

Answer 1

Answer:

Step-by-step explanation:

When you substitute the value of A in the equation you get

((3 \times \sin(60) ) + (2 \times \cos(45) ) \div ((2 \times \cos(60)) - ( \sin(30) ))((3×sin(60))+(2×cos(45))÷((2×cos(60))−(sin(30)))

Substitute the value for sin and cos as follows

Sin 60 = (root(3))/2

Cos 45 = 1/(root (2))

Cos 60 = 1/2

Sin 30 = 1/2

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Answer 2

Answer:

A= 20°

3sin3*20° + 2cos(2*20+5)/2cos3*20 - sin(2*20-10)

3sin60 + 2cos45/2cos60 - sin 30

3*√3/2 + (1/√2)/(1/2) - 1/2

3√3/2 -√2 - 1/2

(1/2)(3√3 - 2√2 - 1)