Question

A 200 g serving bowl is warmed 65C when it absorbs 2600.)Cal of heat from serving of hot food. What is the specific heat of the bowl

Answer 1

Answer:

837.2 J/kg .°C

Explanation:

The mass of the serving bowl, m = 200 g

The change in temperature, ΔT = 65.°C

The heat energy, Q = 2.6 kcal

                                    = ( 2.6 kcal)(1000 Cal/1 kcal)

                                    = 2600 Cal

  The relation between the heat flow and specific heat is

                                     Q = mcΔT

     So, the specific heat of the serving bowl is

                          c = Q/mΔT

                             = (2600 Cal)/(200 g)(65.0°C)

                             = 0.2 Cal/g .°C

Note:

       1 Cal = 4.186 J

         1 g = 10-3 kg

        c = (0.2)(4.186/10-3) J/kg .°C

           = 837.2 J/kg .°C

Hence,

The specific heat of the bowl is 837.2 J/kg .°C