A 200 m long and 65 m broad lawn has two roads at right angles,one 2 m wide, running parallel to its length and the other 2.5 m wide ,running parallel to its breadth. Find the cost of gravelling the roads at rupees 71.50 per square. m
Answers
Answer
Length of the rectangular lawn=75m
Breadth of the lawn=60m
Width of the road=4m
Area of the road(ABCD) parallel to the length of the lawn = 75m×4m
=300m
2
Area of the road(EFGH) parallel to the breadth of the lawn = 60m×4m
=240m
2
Area of the common area in both ABCD and EFGH = 4m×4m
=16m
2
Total area of both the rectangular roads = 300+240−16
=524m
2
Cost of gravelling the roads per m
2
= Rs.4.50
Cost of gravelling the roads for 524m
2
=4.50×524
=2358
Cost of gravelling the road is Rs.2358
Answer:
1) Area. 200x2= 400
2) Area. 63x2.5. 157.50
Total area= 557.50m2
Cost of gravelling
@ Rs.71.50 per m2 = 557.5x7 I.50
= Rs 39861
Step-by-step explanation: