Question

A 200 m long train crosses a platform of double its length in 36 s. What is the speed of the train in km/h

Answer 1

SPEED OF TRAIN IS 40 km/hr

Given:

• Length of train = 200 m
• Time taken = 36 sec
• Length of platform is twice the train length.

To find:

Speed of train ?

Calculation:

So, first of all, let's calculate the length of the platform :

$l_{platform} = 2 \times l_{train}$

$\implies l_{platform} = 2 \times 200$

$\implies l_{platform} = 400 \: m$

Now, net distance covered will be 400+200 = 600 metres.

$speed = \dfrac{distance}{time}$

$\implies speed = \dfrac{400+200}{36}$

$\implies speed = \dfrac{600}{36}$

$\implies speed = \dfrac{100}{6} \: m {s}^{ - 1}$

Now, converting to km/hr

$\implies speed = \dfrac{100}{6} \times \dfrac{ {10}^{ - 3} \: km }{ \frac{1}{3600} \: hr}$

$\implies speed = \dfrac{100}{6} \times \dfrac{18}{5}$

$\implies speed = 60 \: km \: {hr}^{ - 1}$

So, speed of train is 60 km/hr.

Answer 2

The speed of the train is 60km/h.

A 200 m long train crosses a platform of double its length in 36s.

We have to find the speed of the train in km/h.

We know, Speed is the distance covered by a particle per unit time.

i.e., Speed = Distance/Time

Here, train crosses the platform of length is 2 times of length of train.

∴ length of distance covered by train, D = length of train + length of platform

⇒ D = 200m + 2 × 200m = 200m + 400m = 600m

time taken by train to cross the platform, t = 36s

Now, The speed of the train = D/t = 600/36 = (100/6) m/s

We know, 1 m/s = 18/5 km/h

∴ speed of the train in km/h = (100/6) × 18/5 = 20 × 3 = 60 km/h

Therefore the speed of the train is 60km/h.

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