Math, asked by shreyash2379, 1 year ago

A mould has a downsprue whose length is 20 cm and the cross sectional area at the base of the down sprue is 1 cm2. The down sprue feeds a horizontal runner leading into the mould cavity of volume 1000cm3 . The time required to fill the mould cavity will be

Answers

Answered by ferozemulani
1

Step-by-step explanation:

accln due to gravity = 1000 cm/sec^2

velocity of liquid metal =

√(2*1000*20) = 200 cm/sec

time to fill the mould =

volume of mould/(gate area*velocity)

= 1000/(1*200) = 5 sec

Answered by rahul123437
2

The time required to fill the mould cavity = 5.04 sec.

Given:

A mould has a down sprue whose length is 20 cm and the cross sectional area at the base of the down sprue is 1 cm².

The down sprue feeds a horizontal runner leading into the mould cavity of volume 1000cm³.

To find:

The time required to fill the mould cavity will be.

Explanation:

The time required to fill the mould cavity = \frac{Volume \ of \ mould }{Area \times velocity  }

Velocity of sprue = \sqrt{2gh}

h = length of down sprue = 20 cm

g = 981 cm/s²

Velocity of sprue = \sqrt{2gh}

                            =  \sqrt{2\times 981 \times 20}

                            = `198.09 cm/s

Cross sectional area sprue = 1 cm².

mould cavity of volume 1000 cm³

The time required to fill the mould cavity = \frac{Volume \ of \ mould }{Area \times velocity  }

The time required to fill the mould cavity = \frac{1000 }{1\times 198.02 } = 5.04 sec.

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