A 200kg motorcycle is moving over a horizontal road with uniform velocity. If this motorcycle has to be stopped with a negative aceleration of 1.5m/s^2, hence what is the force of friction between the type of the motorcycle and the road
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In the question we are given that the mass of the motorcycle is =2000kg and
acceleration = — 1.5 ms–2 so from newton's second law by using
F = ma
F = –2000 kg ×1.5ms -2
F = – 3000kg ms–2
F = –3000N
hence the force of friction between the tyres of the motorcycle and the road is 3000 N
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