Question

A 200kg motorcycle is moving over a horizontal road with uniform velocity. If this motorcycle has to be stopped with negative acceleration of 1.5m/s then what is the friction between tyre and road?

Answer 1

Given:

200kg motorcycle is moving over a horizontal road with uniform velocity. This motorcycle has to be stopped with negative acceleration of 1.5 m/s².

To find:

Friction between tyre and road.

Calculation:

The motorcycle was moving on the road with a constant velocity. Now, due to to friction between the tyres and the road, the motorcycle stops. Hence, the friction acts as the stopping force for the object.

$\rm{ \therefore \: friction =stopping \: force}$

$\rm{ = > \: friction =mass \times acceleration}$

$\rm{ = > \: friction =200 \times 1.5}$

$\rm{ = > \: friction =300 \: N }$

So , final answer is :

$\boxed{ \sf{ \red{ \: friction =300 \: N }}}$

Answer 2

Explanation:

200kg motorcycle is moving over a horizontal road with uniform velocity. This motorcycle has to be stopped with negative acceleration of 1.5 m/s².

To find:

Friction between tyre and road.

Calculation:

The motorcycle was moving on the road with a constant velocity. Now, due to to friction between the tyres and the road, the motorcycle stops. Hence, the friction acts as the stopping force for the object.

\rm{ \therefore \: friction =stopping \: force}∴friction=stoppingforce

\rm{ = > \: friction =mass \times acceleration}=>friction=mass×acceleration

\rm{ = > \: friction =200 \times 1.5}=>friction=200×1.5

\rm{ = > \: friction =300 \: N }=>friction=300N

So , final answer is :

\boxed{ \sf{ \red{ \: friction =300 \: N }}}

friction=300N