Question

a^2020*b^2019 = 1/2 and a^2018*b^2021 = (64)^1/2, then a^2b^3 =

Answer 1

Step-by-step explanation:

> a2+b2+c2+3-2a-2b-2c =0 ... ie; all the three terms shd be 0. so (a−1)2 =(b−1)2=(c−1)2=0. a=b=c=1

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