a 20kg load is suspended by a wire of cross section 0.4 mm² The stress produced in Nm-2 is
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Given :
Mass = 20 kg
Area of cross section = 0.4 mm² = 0.4 × 10¯⁶m²
To Find :
The stress produced
Solution :
Stress is the external force per unit area of the body,
by substituting the values in the formula,
Thus, the stress produced by the body is 5 × 10⁸ N/m².
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