Question

A 2100W continuous flow geyser has water inlet temperature 10C while water flows out at rate 20g/s. outlet temperature is

Answer 1

according to calorimetry,
Heat loss = Heat gain

geyser flow 2100J heat per second to water.
hence, Heat loss by Geyser = 2100J
and Heat gain by water = Q = mc∆T
= 20g × 4200J/kg/°C × (T - 10)

now, 2100 = 20/1000 × 4200 × (T - 10)
2100 = 2 × 42 × (T - 10)
25 + 10 = T
T = 35°C

hence, outlet temperature of water is 35°C

Answer 2

Answer:

35°C

Explanation:

2100 Watt = 2100 j/s

Temperature = 10°C

mass = 20g

C = 4.2 joul

Q = mC∆T

2100 = 20 × 4.2 × (T-10)

2100 = 84 × (T-10)

2100/84 = T-10

25 = T-10

25+10 = T

so, T = 35°c