Question

a) 212 kg 2 hg 5 dag 8 g=____________kg
b) 5 hg 8 dag 6 g=___________kg
c) 28 kg 7 g=__________kg
d) 3 dag=__________kg

Answer 1

Answer:

a) 212kg 2hg 5 dag 8g

= 212kg+2hg+5dag+8g

= 212kg+ 2/10kg+ 5/100kg+8/1000kg

hope it helps

3kg 7hg 8dag 1g=3781

9kg 1hg 5dag 4g=9154

The greatest weight required is G.C.F. of 3781 and 9154

Using Euclid algorithm

9154=3781×2+1592

3781=1592×2+597

1592=597×2+398

597=398×1+199

398=199×2+0

Hence greatest weight =1hg 9dag 9g

Answer 2

Step-by-step explanation:

7550 g = 7 kg 550 g

3255 g = 3 kg 255 g

12 kg 250 g = 12250 g

18 kg 368 g = 18368 g