Question

A 25 m long ladder is placed against a Vertical such that the foot of the ladder is 7m from the foot of the wall. If the top of the ladder slides down by 4m‚ by how much distance will the foot of the ladder slides?​

Answer 1

Answer:

12m

Step be step explanation:

present distance of ladder from foot of wall to top of ladder = x

(using pythagoras)

25^2 - 7^2 = x^2

625 - 49 = 576

=24^2

= 24 m

the ladder slides down 4 m

after sliding, dts. of ladder top from foot of wall = 24m - 4m = 20m

to find - dts. of foot of ladder from foot of wall (y)

(using Pythagoras)

20^2 - 7^2 = y^2

400 - 49 = 361

=19^2

= 19 m

Hence, it slid (19-7)m.

= 12 m